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(1/x+1%1/1%x) 怎么解?

是不是(1/(x+1)-1/(1-x))? 1/(x+1)-1/(1-x) =1/(x+1)+1/(x-1) =(x-1)/((x+1)(x-1)) + (x+1)/((x+1)(x-1))\ =((x-1)+ (x+1))/((x+1)(x-1)) =2x/((x+1)(x-1)) =2x/(x^2-1)

解:原不等式等价于: -1

解:(1+x)/(1-x)>1 当1-x>0时,即x1-x 2x>0 x>0 综合一下,0

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