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2/3x%1/5=x/2 解?

如图

解:依题意得方程组, 3x-5y=3 (1) 2分之1x-3分之1y=1 (2) 由(2)得 3x-2y=6 (3) (3)-(1)得 3x-2y-(3x-5y)=6-3 3x-2y-3x+5y=3 3y=3 y=3÷3 y=1 将y=1带入(1)得 3x-5×1=3 3x-5=3 3x=3+5 3x=8 x=8÷3 x=3分之8 即x=3分之8,y=1

y = (x-1)|x2-3x+2| = (x-1)|(x-1)(x-2)| x<1时,或x>2时: y=(x-1)(x-1)(x+2)=(x-1)2(x-2) y′=2(x-1)(x+2)+(x-1)2=(x-1)(3x-5) 1≤x≤2时: y = - (x-1)2(x-2) y′ = -(x-1)(3x-5) x趋近2-时,y′趋近-(2-1)(6-5)=-1 x趋近2+时,y′趋近(2-1)(6-5)...

1/2 1.2满意请采纳

3x-1/5=x+7/2 30x-2=10x+35 30x-10x=35+2=37 20x=37 x=37/20

48:1/5x=2/3x:1 48/(x/5)=2x/3 48*5/x=2x/3 两边同乘以3x得, 240*3=2x^2 两边同除以2得, 360=x^2 移项得 x^2-360=0 (x-6√10)(x+6√10)=0 x-6√10=0或x+6√10=0 ∴ x1=6√10,x2=-6√10

见图

1/(x^2+x)+1/(x^2+3x+2)+1/(x^2+5x+6)+1/(x^2+7x+12)+1/(x^2+9x+20) =1/x(x+1)+ 1/(x+1)(x+2) + 1/(x+2)(x+3)+ 1/(x+3)(x+4)+ 1/(x+4)(x+5) =[1/x - 1/(x+1)]+[1/(x+1) - 1/(x+2)]+[1/(x+2) - 1/(x+3)]+[1/(x+3) - 1/(x+4)]+[1/(x+4) - 1/...

(4.5-x)*7=17.5 4.5-x=17.5/7 x=4.5-2.5 x=2 x/2+4=3/2x+1 x/2-3x/2=1-4 x=3 7/2*2/3-4x=7/3 7/3-4x=7/3 x=0 5/8(x-.3)=75% x-3=3/4*8/5 x=3+6/5 x=21/5 (1+x)/4=4:5 1+x=4*4/5 x=11/5

1..若代数式5-3x/2比代数式3-5x/3大1,求x的值 5 - 3x/2 - (3 - 5x/3) = 1 5 - 3X/2 - 3 + 5X/3 = 1 1 = 3X/2 - 5X/3 - X/6 = 1 X = - 6 2.已知方程(2a+1)x=3ax-4有正整数解,求整数a可能的值 (2a+1)x=3ax-4 (3A - 2A - 1)X = 4 X = 4/(A - ...

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