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jQuEry遍历json数组怎么整

var str = eval('[{"id":1,"sex":"","age":2,"userName":"1","job":"","password":""},{"id":2,"sex":"","age":2,"userName":"1","job":"","password":""}]');$.each(str, function() {alert(this.id);});自行参考。

var jarr=[{a:'1'},{a:'2'}]; $(jarr).each(function(k,v){ alert(v.a); });

// by sleest 2016/05/10var res='{"list":[{"id":3010,"name":"青海","cityList":[{"id":3011,"name":"西宁"},{"id":3012,"name":"城东区"},{"id":3013,"name":"城西区"}]}]}';var dataObj = JSON.parse(res);var listData = dataObj.list;var ...

我也看烦了,看着似乎有点明白,但又不怎么明白,先把代码写出来,再说说你这个json 代码如下: $.each(h, function () {//h就是你的json了 var h1 = this; alert("a:" + h1.a); $.each(h1.a1, function () { var h2 = this; alert("a2:" + h2.a...

var obj = {"id": 1, "name":"张三"}; for(var key in obj) { alert("Key是:" + key); alert("对应的值是:" + obj[key]); }

看你json串的格式。比如{"id":"1","name":"张三"},{"id":"2","name":"李四"} 这种接近于数组,遍历方式可以for(var i = 0; i = list.size(); i ++) 也可以用for( var a in list)的方式来遍历,方法很多就不一一解释了。 也不一定非要用jQuery遍...

$.getJSON(url,function(json){ $.each(json,function(i,item){item.key3.subkey[0].ssubkey1-->ssubval1});});

这和各浏览器的Map键名的遍历方法相关,jquery只不过是包装了一下 for (key in obj)。 解决方法为将键名放入的数组,通过遍历数组的方式就不会有问题了。 var a = []; $.each(obj, function(key, val) { a[a.length] = key; }); a.sort(); $.eac...

alert($(this).nidString);或者alert(list[i].nidString);有试过吗?

jquery code如下: $(function(){ var data=[ {"id":"3","topid":"1","sortrank":"1","typename":"\u516c\u53f8\u7b80\u4ecb","typedir":"cmspath}\/html\/about\/aboutus","tpeimg":"","description":"","keywords":"","content":""}, {"id":"4"...

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