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x÷x=2x,x是多少?

2X÷X=: 在x不等于0时:2X÷X=2 x等于0时,算式是不成立的。

x²-2x=2 (x-1)²=3 ∴x-1=√3 x-1=-√3 舍去 =(x+1)(x-1)/x(x+1) ÷(x²-2x+1)/x =(x-1)/x×x/(x-1)² =1/(x-1) =1/√3 =√3/3

2x³÷x² =2x^(3-2) =2x^1 =2x

2X=16X8 2X=128 X=128÷2 X=64

x-2x/2-6÷(x-5/2-x-2) =x-x-6÷(-9/2) =-6*(-2/9) =4/3

(2x/x-2-x/x+2)÷x/x^2-4 =(2/x-2-1/x+2)÷1/x^2-4 =(2/x-2-1/x+2)×(x^2-4) =2/(x-2)×(x^2-4)-1/(x+2)×(x^2-4) =2(x+2)-(x-2) =2x+4-x+2 =x+6

原式=( x x-5 + x x-5 )? x 2 -25 2x = 2x x-5 ? (x+5)(x-5) 2x =x+5,解不等式①,得x≥-5,解不等式②,得x<6,∴不等式组的解集为-5≤x<6,取x=1时,原式=6.本题答案不唯一.

(x+2)/(2x²-4x )÷ [(x-2)+(8x/(x-2)] = [(x+2)/2x(x-2 )]÷ [(x-2)^2+8x]/(x-2) = [(x+2)/2x(x-2 )]*[(x-2)/(x+2)^2] =1/x(x+2) x=√2 -1. 原式=1/x(x+2) =1/[(√2 -1)(√2 +1)] =1/(2-1) =1

不正确,错误之处在于先算了乘法,再算除法.正确的解答过程是:原式=x?1x?2?1x?2=x(x?2)2.

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